Solve for x
x=6
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\left(2x-7\right)\left(x+1\right)=\left(x-1\right)\left(2x-5\right)
Variable x cannot be equal to any of the values 1,\frac{7}{2} since division by zero is not defined. Multiply both sides of the equation by \left(x-1\right)\left(2x-7\right), the least common multiple of x-1,2x-7.
2x^{2}-5x-7=\left(x-1\right)\left(2x-5\right)
Use the distributive property to multiply 2x-7 by x+1 and combine like terms.
2x^{2}-5x-7=2x^{2}-7x+5
Use the distributive property to multiply x-1 by 2x-5 and combine like terms.
2x^{2}-5x-7-2x^{2}=-7x+5
Subtract 2x^{2} from both sides.
-5x-7=-7x+5
Combine 2x^{2} and -2x^{2} to get 0.
-5x-7+7x=5
Add 7x to both sides.
2x-7=5
Combine -5x and 7x to get 2x.
2x=5+7
Add 7 to both sides.
2x=12
Add 5 and 7 to get 12.
x=\frac{12}{2}
Divide both sides by 2.
x=6
Divide 12 by 2 to get 6.
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