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\left(x-1\right)\left(x+1\right)=x\left(x+6\right)
Variable x cannot be equal to any of the values 0,1 since division by zero is not defined. Multiply both sides of the equation by x\left(x-1\right), the least common multiple of x,x-1.
x^{2}-1=x\left(x+6\right)
Consider \left(x-1\right)\left(x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
x^{2}-1=x^{2}+6x
Use the distributive property to multiply x by x+6.
x^{2}-1-x^{2}=6x
Subtract x^{2} from both sides.
-1=6x
Combine x^{2} and -x^{2} to get 0.
6x=-1
Swap sides so that all variable terms are on the left hand side.
x=\frac{-1}{6}
Divide both sides by 6.
x=-\frac{1}{6}
Fraction \frac{-1}{6} can be rewritten as -\frac{1}{6} by extracting the negative sign.