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\left(x+1\right)\left(x+1\right)=\left(x+2\right)\left(x-3\right)
Variable x cannot be equal to any of the values -2,-1 since division by zero is not defined. Multiply both sides of the equation by \left(x+1\right)\left(x+2\right), the least common multiple of x+2,x+1.
\left(x+1\right)^{2}=\left(x+2\right)\left(x-3\right)
Multiply x+1 and x+1 to get \left(x+1\right)^{2}.
x^{2}+2x+1=\left(x+2\right)\left(x-3\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
x^{2}+2x+1=x^{2}-x-6
Use the distributive property to multiply x+2 by x-3 and combine like terms.
x^{2}+2x+1-x^{2}=-x-6
Subtract x^{2} from both sides.
2x+1=-x-6
Combine x^{2} and -x^{2} to get 0.
2x+1+x=-6
Add x to both sides.
3x+1=-6
Combine 2x and x to get 3x.
3x=-6-1
Subtract 1 from both sides.
3x=-7
Subtract 1 from -6 to get -7.
x=\frac{-7}{3}
Divide both sides by 3.
x=-\frac{7}{3}
Fraction \frac{-7}{3} can be rewritten as -\frac{7}{3} by extracting the negative sign.