Solve for x
x\leq \frac{7}{2}
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x+1\leq 15-3x
Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.
x+1+3x\leq 15
Add 3x to both sides.
4x+1\leq 15
Combine x and 3x to get 4x.
4x\leq 15-1
Subtract 1 from both sides.
4x\leq 14
Subtract 1 from 15 to get 14.
x\leq \frac{14}{4}
Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.
x\leq \frac{7}{2}
Reduce the fraction \frac{14}{4} to lowest terms by extracting and canceling out 2.
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