Solve x+1/3+1=y-1/3-1

$$\frac { x + 1 } { 3 + 1 } = \frac { y - 1 } { 3 - 1 }$$

Solve for x

$$x=2y-3$$

Steps for Solving Linear Equation

Add 3 and 1 to get 4.

$$\frac{x+1}{4}=\frac{y-1}{3-1}$$

Subtract 1 from 3 to get 2.

$$\frac{x+1}{4}=\frac{y-1}{2}$$

Divide each term of x+1 by 4 to get \frac{1}{4}x+\frac{1}{4}.

$$\frac{1}{4}x+\frac{1}{4}=\frac{y-1}{2}$$

Divide each term of y-1 by 2 to get \frac{1}{2}y-\frac{1}{2}.

$$\frac{1}{4}x+\frac{1}{4}=\frac{1}{2}y-\frac{1}{2}$$

Subtract \frac{1}{4} from both sides.

$$\frac{1}{4}x=\frac{1}{2}y-\frac{1}{2}-\frac{1}{4}$$

Subtract \frac{1}{4} from -\frac{1}{2} to get -\frac{3}{4}.

$$\frac{1}{4}x=\frac{1}{2}y-\frac{3}{4}$$

The equation is in standard form.

$$\frac{1}{4}x=\frac{y}{2}-\frac{3}{4}$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{\frac{y}{2}-\frac{3}{4}}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=\frac{\frac{y}{2}-\frac{3}{4}}{\frac{1}{4}}$$

Divide \frac{y}{2}-\frac{3}{4} by \frac{1}{4} by multiplying \frac{y}{2}-\frac{3}{4} by the reciprocal of \frac{1}{4}.

$$x=2y-3$$

Solve for y

$$y=\frac{x+3}{2}$$

Steps for Solving Linear Equation

Add 3 and 1 to get 4.

$$\frac{x+1}{4}=\frac{y-1}{3-1}$$

Subtract 1 from 3 to get 2.

$$\frac{x+1}{4}=\frac{y-1}{2}$$

Divide each term of x+1 by 4 to get \frac{1}{4}x+\frac{1}{4}.

$$\frac{1}{4}x+\frac{1}{4}=\frac{y-1}{2}$$

Divide each term of y-1 by 2 to get \frac{1}{2}y-\frac{1}{2}.

$$\frac{1}{4}x+\frac{1}{4}=\frac{1}{2}y-\frac{1}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}y-\frac{1}{2}=\frac{1}{4}x+\frac{1}{4}$$

Add \frac{1}{2} to both sides.

$$\frac{1}{2}y=\frac{1}{4}x+\frac{1}{4}+\frac{1}{2}$$

Add \frac{1}{4} and \frac{1}{2} to get \frac{3}{4}.

$$\frac{1}{2}y=\frac{1}{4}x+\frac{3}{4}$$

The equation is in standard form.

$$\frac{1}{2}y=\frac{x+3}{4}$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{x+3}{\frac{1}{2}\times 4}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{x+3}{\frac{1}{2}\times 4}$$

Divide \frac{3+x}{4} by \frac{1}{2} by multiplying \frac{3+x}{4} by the reciprocal of \frac{1}{2}.

$$y=\frac{x+3}{2}$$