Solve v-2/v^2+2v-3*v^2+2v-3/v-4

$$\frac { v - 2 } { v ^ { 2 } + 2 v - 3 } \cdot \frac { v ^ { 2 } + 2 v - 3 } { v - 4 }$$

Evaluate

$$\frac{v-2}{v-4}$$

Short Solution Steps

Multiply \frac{v-2}{v^{2}+2v-3} times \frac{v^{2}+2v-3}{v-4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(v-2\right)\left(v^{2}+2v-3\right)}{\left(v^{2}+2v-3\right)\left(v-4\right)}$$

Cancel out v^{2}+2v-3 in both numerator and denominator.

$$\frac{v-2}{v-4}$$

Expand

$$\frac{v-2}{v-4}$$

Short Solution Steps

Multiply \frac{v-2}{v^{2}+2v-3} times \frac{v^{2}+2v-3}{v-4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(v-2\right)\left(v^{2}+2v-3\right)}{\left(v^{2}+2v-3\right)\left(v-4\right)}$$

Cancel out v^{2}+2v-3 in both numerator and denominator.

$$\frac{v-2}{v-4}$$