Solve for t
t=11
t=-10
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t\left(t-1\right)=55\times 2
Multiply both sides by 2.
t^{2}-t=55\times 2
Use the distributive property to multiply t by t-1.
t^{2}-t=110
Multiply 55 and 2 to get 110.
t^{2}-t-110=0
Subtract 110 from both sides.
t=\frac{-\left(-1\right)±\sqrt{1-4\left(-110\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -110 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{-\left(-1\right)±\sqrt{1+440}}{2}
Multiply -4 times -110.
t=\frac{-\left(-1\right)±\sqrt{441}}{2}
Add 1 to 440.
t=\frac{-\left(-1\right)±21}{2}
Take the square root of 441.
t=\frac{1±21}{2}
The opposite of -1 is 1.
t=\frac{22}{2}
Now solve the equation t=\frac{1±21}{2} when ± is plus. Add 1 to 21.
t=11
Divide 22 by 2.
t=-\frac{20}{2}
Now solve the equation t=\frac{1±21}{2} when ± is minus. Subtract 21 from 1.
t=-10
Divide -20 by 2.
t=11 t=-10
The equation is now solved.
t\left(t-1\right)=55\times 2
Multiply both sides by 2.
t^{2}-t=55\times 2
Use the distributive property to multiply t by t-1.
t^{2}-t=110
Multiply 55 and 2 to get 110.
t^{2}-t+\left(-\frac{1}{2}\right)^{2}=110+\left(-\frac{1}{2}\right)^{2}
Divide -1, the coefficient of the x term, by 2 to get -\frac{1}{2}. Then add the square of -\frac{1}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
t^{2}-t+\frac{1}{4}=110+\frac{1}{4}
Square -\frac{1}{2} by squaring both the numerator and the denominator of the fraction.
t^{2}-t+\frac{1}{4}=\frac{441}{4}
Add 110 to \frac{1}{4}.
\left(t-\frac{1}{2}\right)^{2}=\frac{441}{4}
Factor t^{2}-t+\frac{1}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(t-\frac{1}{2}\right)^{2}}=\sqrt{\frac{441}{4}}
Take the square root of both sides of the equation.
t-\frac{1}{2}=\frac{21}{2} t-\frac{1}{2}=-\frac{21}{2}
Simplify.
t=11 t=-10
Add \frac{1}{2} to both sides of the equation.
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