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t+6>0 t-1<0
For the quotient to be negative, t+6 and t-1 have to be of the opposite signs. Consider the case when t+6 is positive and t-1 is negative.
t\in \left(-6,1\right)
The solution satisfying both inequalities is t\in \left(-6,1\right).
t-1>0 t+6<0
Consider the case when t-1 is positive and t+6 is negative.
t\in \emptyset
This is false for any t.
t\in \left(-6,1\right)
The final solution is the union of the obtained solutions.