Solve t+1/9div-t-1/3

$$\frac { t + 1 } { 9 } \div \frac { - t - 1 } { 3 }$$

Evaluate

$$-\frac{1}{3}\approx -0.333333333$$

Short Solution Steps

Divide \frac{t+1}{9} by \frac{-t-1}{3} by multiplying \frac{t+1}{9} by the reciprocal of \frac{-t-1}{3}.

$$\frac{\left(t+1\right)\times 3}{9\left(-t-1\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{t+1}{3\left(-t-1\right)}$$

Extract the negative sign in t+1.

$$\frac{-\left(-t-1\right)}{3\left(-t-1\right)}$$

Cancel out -t-1 in both numerator and denominator.

$$\frac{-1}{3}$$

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$-\frac{1}{3}$$

Factor

$$-\frac{1}{3} = -0.3333333333333333$$