Solve s/w^2=w-4/3w^2+c/3w^2

$$\frac { s } { w ^ { 2 } } = \frac { w - 4 } { 3 w ^ { 2 } } + \frac { c } { 3 w ^ { 2 } }$$

Solve for c

$$c=3s-w+4$$

$$w\neq 0$$

Solution Steps

Multiply both sides of the equation by 3w^{2}, the least common multiple of w^{2},3w^{2}.

$$3s=w-4+c$$

Swap sides so that all variable terms are on the left hand side.

$$w-4+c=3s$$

Subtract w from both sides.

$$-4+c=3s-w$$

Add 4 to both sides.

$$c=3s-w+4$$

Solve for s

$$s=\frac{w+c-4}{3}$$

$$w\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3w^{2}, the least common multiple of w^{2},3w^{2}.

$$3s=w-4+c$$

Reorder the terms.

$$3s=w+c-4$$

Divide both sides by 3.

$$\frac{3s}{3}=\frac{w+c-4}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$s=\frac{w+c-4}{3}$$