Solve s/d=5qc

$$\frac { s } { d } = 5 q c$$

Solve for c

$$\left\{\begin{matrix}c=\frac{s}{5dq}\text{, }&q\neq 0\text{ and }d\neq 0\\c\in \mathrm{R}\text{, }&s=0\text{ and }q=0\text{ and }d\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by d.

$$s=5qcd$$

Swap sides so that all variable terms are on the left hand side.

$$5qcd=s$$

The equation is in standard form.

$$5dqc=s$$

Divide both sides by 5qd.

$$\frac{5dqc}{5dq}=\frac{s}{5dq}$$

Dividing by 5qd undoes the multiplication by 5qd.

$$c=\frac{s}{5dq}$$

Solve for d

$$\left\{\begin{matrix}d=\frac{s}{5cq}\text{, }&s\neq 0\text{ and }c\neq 0\text{ and }q\neq 0\\d\neq 0\text{, }&\left(q=0\text{ or }c=0\right)\text{ and }s=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable d cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by d.

$$s=5qcd$$

Swap sides so that all variable terms are on the left hand side.

$$5qcd=s$$

The equation is in standard form.

$$5cqd=s$$

Divide both sides by 5qc.

$$\frac{5cqd}{5cq}=\frac{s}{5cq}$$

Dividing by 5qc undoes the multiplication by 5qc.

$$d=\frac{s}{5cq}$$

Variable d cannot be equal to 0.

$$d=\frac{s}{5cq}\text{, }d\neq 0$$