Solve p-64/p/p+frac{64{p}}

$$\frac { p - \frac { 64 } { p } } { p + \frac { 64 } { p } }$$

Evaluate

$$\frac{p^{2}-64}{p^{2}+64}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply p times \frac{p}{p}.

$$\frac{\frac{pp}{p}-\frac{64}{p}}{p+\frac{64}{p}}$$

Since \frac{pp}{p} and \frac{64}{p} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{pp-64}{p}}{p+\frac{64}{p}}$$

Do the multiplications in pp-64.

$$\frac{\frac{p^{2}-64}{p}}{p+\frac{64}{p}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply p times \frac{p}{p}.

$$\frac{\frac{p^{2}-64}{p}}{\frac{pp}{p}+\frac{64}{p}}$$

Since \frac{pp}{p} and \frac{64}{p} have the same denominator, add them by adding their numerators.

$$\frac{\frac{p^{2}-64}{p}}{\frac{pp+64}{p}}$$

Do the multiplications in pp+64.

$$\frac{\frac{p^{2}-64}{p}}{\frac{p^{2}+64}{p}}$$

Divide \frac{p^{2}-64}{p} by \frac{p^{2}+64}{p} by multiplying \frac{p^{2}-64}{p} by the reciprocal of \frac{p^{2}+64}{p}.

$$\frac{\left(p^{2}-64\right)p}{p\left(p^{2}+64\right)}$$

Cancel out p in both numerator and denominator.

$$\frac{p^{2}-64}{p^{2}+64}$$

Expand

$$\frac{p^{2}-64}{p^{2}+64}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply p times \frac{p}{p}.

$$\frac{\frac{pp}{p}-\frac{64}{p}}{p+\frac{64}{p}}$$

Since \frac{pp}{p} and \frac{64}{p} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{pp-64}{p}}{p+\frac{64}{p}}$$

Do the multiplications in pp-64.

$$\frac{\frac{p^{2}-64}{p}}{p+\frac{64}{p}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply p times \frac{p}{p}.

$$\frac{\frac{p^{2}-64}{p}}{\frac{pp}{p}+\frac{64}{p}}$$

Since \frac{pp}{p} and \frac{64}{p} have the same denominator, add them by adding their numerators.

$$\frac{\frac{p^{2}-64}{p}}{\frac{pp+64}{p}}$$

Do the multiplications in pp+64.

$$\frac{\frac{p^{2}-64}{p}}{\frac{p^{2}+64}{p}}$$

Divide \frac{p^{2}-64}{p} by \frac{p^{2}+64}{p} by multiplying \frac{p^{2}-64}{p} by the reciprocal of \frac{p^{2}+64}{p}.

$$\frac{\left(p^{2}-64\right)p}{p\left(p^{2}+64\right)}$$

Cancel out p in both numerator and denominator.

$$\frac{p^{2}-64}{p^{2}+64}$$