Solve mn^2/6k*9mj/4kn=

$$\frac { m n ^ { 2 } } { 6 k } \times \frac { 9 m j } { 4 k n } =$$

Evaluate

$$\frac{3\times \left(\frac{m}{k}\right)^{2}jn}{8}$$

Solution Steps

Multiply \frac{mn^{2}}{6k} times \frac{9mj}{4kn} by multiplying numerator times numerator and denominator times denominator.

$$\frac{mn^{2}\times 9mj}{6k\times 4kn}$$

Cancel out 3n in both numerator and denominator.

$$\frac{3jmmn}{2\times 4kk}$$

Multiply m and m to get m^{2}.

$$\frac{3jm^{2}n}{2\times 4kk}$$

Multiply k and k to get k^{2}.

$$\frac{3jm^{2}n}{2\times 4k^{2}}$$

Multiply 2 and 4 to get 8.

$$\frac{3jm^{2}n}{8k^{2}}$$

Differentiate w.r.t. j

$$\frac{3\times \left(\frac{m}{k}\right)^{2}n}{8}$$