Solve m/m+m/m=(1/3)/-4+frac{-4}{(frac{1}{3})}=frac{1}{-12}

$$\frac { m } { m } + \frac { m } { m } = \frac { ( \frac { 1 } { 3 } ) } { - 4 } + \frac { - 4 } { ( \frac { 1 } { 3 } ) } = \frac { 1 } { - 12 }$$

Evaluate

Solution Steps

Divide m by m to get 1.

$$1+\frac{m}{m}=\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Divide m by m to get 1.

$$1+1=\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Add 1 and 1 to get 2.

$$2=\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Express \frac{\frac{1}{3}}{-4} as a single fraction.

$$2=\frac{1}{3\left(-4\right)}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Multiply 3 and -4 to get -12.

$$2=\frac{1}{-12}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Fraction \frac{1}{-12} can be rewritten as -\frac{1}{12} by extracting the negative sign.

$$2=-\frac{1}{12}+\frac{-4}{\frac{1}{3}}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Divide -4 by \frac{1}{3} by multiplying -4 by the reciprocal of \frac{1}{3}.

$$2=-\frac{1}{12}-4\times 3\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Multiply -4 and 3 to get -12.

$$2=-\frac{1}{12}-12\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Convert 12 to fraction \frac{144}{12}.

$$2=-\frac{1}{12}-\frac{144}{12}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Since -\frac{1}{12} and \frac{144}{12} have the same denominator, subtract them by subtracting their numerators.

$$2=\frac{-1-144}{12}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Subtract 144 from -1 to get -145.

$$2=-\frac{145}{12}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Convert 2 to fraction \frac{24}{12}.

$$\frac{24}{12}=-\frac{145}{12}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Compare \frac{24}{12} and -\frac{145}{12}.

$$\text{false}\text{ and }\frac{\frac{1}{3}}{-4}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Express \frac{\frac{1}{3}}{-4} as a single fraction.

$$\text{false}\text{ and }\frac{1}{3\left(-4\right)}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Multiply 3 and -4 to get -12.

$$\text{false}\text{ and }\frac{1}{-12}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Fraction \frac{1}{-12} can be rewritten as -\frac{1}{12} by extracting the negative sign.

$$\text{false}\text{ and }-\frac{1}{12}+\frac{-4}{\frac{1}{3}}=\frac{1}{-12}$$

Divide -4 by \frac{1}{3} by multiplying -4 by the reciprocal of \frac{1}{3}.

$$\text{false}\text{ and }-\frac{1}{12}-4\times 3=\frac{1}{-12}$$

Multiply -4 and 3 to get -12.

$$\text{false}\text{ and }-\frac{1}{12}-12=\frac{1}{-12}$$

Convert 12 to fraction \frac{144}{12}.

$$\text{false}\text{ and }-\frac{1}{12}-\frac{144}{12}=\frac{1}{-12}$$

Since -\frac{1}{12} and \frac{144}{12} have the same denominator, subtract them by subtracting their numerators.

$$\text{false}\text{ and }\frac{-1-144}{12}=\frac{1}{-12}$$

Subtract 144 from -1 to get -145.

$$\text{false}\text{ and }-\frac{145}{12}=\frac{1}{-12}$$

Fraction \frac{1}{-12} can be rewritten as -\frac{1}{12} by extracting the negative sign.

$$\text{false}\text{ and }-\frac{145}{12}=-\frac{1}{12}$$

Compare -\frac{145}{12} and -\frac{1}{12}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$