Solve k-1/-2=-6/4c

$$\frac { k - 1 } { - 2 } = \frac { - 6 } { 4 c }$$

Solve for c

$$c=-\frac{3}{1-k}$$

$$k\neq 1$$

Steps for Solving Linear Equation

Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4c, the least common multiple of -2,4c.

$$-2c\left(k-1\right)=-6$$

Use the distributive property to multiply -2c by k-1.

$$-2ck+2c=-6$$

Combine all terms containing c.

$$\left(-2k+2\right)c=-6$$

The equation is in standard form.

$$\left(2-2k\right)c=-6$$

Divide both sides by -2k+2.

$$\frac{\left(2-2k\right)c}{2-2k}=-\frac{6}{2-2k}$$

Dividing by -2k+2 undoes the multiplication by -2k+2.

$$c=-\frac{6}{2-2k}$$

Divide -6 by -2k+2.

$$c=-\frac{3}{1-k}$$

Variable c cannot be equal to 0.

$$c=-\frac{3}{1-k}\text{, }c\neq 0$$

Solve for k

$$k=\frac{c+3}{c}$$

$$c\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4c, the least common multiple of -2,4c.

$$-2c\left(k-1\right)=-6$$

Use the distributive property to multiply -2c by k-1.

$$-2ck+2c=-6$$

Subtract 2c from both sides.

$$-2ck=-6-2c$$

The equation is in standard form.

$$\left(-2c\right)k=-2c-6$$

Divide both sides by -2c.

$$\frac{\left(-2c\right)k}{-2c}=\frac{-2c-6}{-2c}$$

Dividing by -2c undoes the multiplication by -2c.

$$k=\frac{-2c-6}{-2c}$$

Divide -6-2c by -2c.

$$k=1+\frac{3}{c}$$