Solve k^2+3k-10/36*3/k^2-4

$$\frac { k ^ { 2 } + 3 k - 10 } { 36 } \cdot \frac { 3 } { k ^ { 2 } - 4 }$$

Evaluate

$$\frac{k+5}{12\left(k+2\right)}$$

Short Solution Steps

Multiply \frac{k^{2}+3k-10}{36} times \frac{3}{k^{2}-4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(k^{2}+3k-10\right)\times 3}{36\left(k^{2}-4\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{k^{2}+3k-10}{12\left(k^{2}-4\right)}$$

Factor the expressions that are not already factored.

$$\frac{\left(k-2\right)\left(k+5\right)}{12\left(k-2\right)\left(k+2\right)}$$

Cancel out k-2 in both numerator and denominator.

$$\frac{k+5}{12\left(k+2\right)}$$

Expand the expression.

$$\frac{k+5}{12k+24}$$

Expand

$$\frac{k+5}{12\left(k+2\right)}$$

Short Solution Steps

Multiply \frac{k^{2}+3k-10}{36} times \frac{3}{k^{2}-4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(k^{2}+3k-10\right)\times 3}{36\left(k^{2}-4\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{k^{2}+3k-10}{12\left(k^{2}-4\right)}$$

Factor the expressions that are not already factored.

$$\frac{\left(k-2\right)\left(k+5\right)}{12\left(k-2\right)\left(k+2\right)}$$

Cancel out k-2 in both numerator and denominator.

$$\frac{k+5}{12\left(k+2\right)}$$

Expand the expression.

$$\frac{k+5}{12k+24}$$