Solve k^2+15k+56/3k+21divk+8/10

$$\frac { k ^ { 2 } + 15 k + 56 } { 3 k + 21 } \div \frac { k + 8 } { 10 }$$

Evaluate

$$\frac{10}{3}\approx 3.333333333$$

Short Solution Steps

Divide \frac{k^{2}+15k+56}{3k+21} by \frac{k+8}{10} by multiplying \frac{k^{2}+15k+56}{3k+21} by the reciprocal of \frac{k+8}{10}.

$$\frac{\left(k^{2}+15k+56\right)\times 10}{\left(3k+21\right)\left(k+8\right)}$$

Factor the expressions that are not already factored.

$$\frac{10\left(k+7\right)\left(k+8\right)}{3\left(k+7\right)\left(k+8\right)}$$

Cancel out \left(k+7\right)\left(k+8\right) in both numerator and denominator.

$$\frac{10}{3}$$

Factor

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$