Solve j-8/j+10=j-1/j+3

$$\frac { j - 8 } { j + 10 } = \frac { j - 1 } { j + 3 }$$

Solve for j

$$j=-1$$

Steps for Solving Linear Equation

Variable j cannot be equal to any of the values -10,-3 since division by zero is not defined. Multiply both sides of the equation by \left(j+3\right)\left(j+10\right), the least common multiple of j+10,j+3.

$$\left(j+3\right)\left(j-8\right)=\left(j+10\right)\left(j-1\right)$$

Use the distributive property to multiply j+3 by j-8 and combine like terms.

$$j^{2}-5j-24=\left(j+10\right)\left(j-1\right)$$

Use the distributive property to multiply j+10 by j-1 and combine like terms.

$$j^{2}-5j-24=j^{2}+9j-10$$

Subtract j^{2} from both sides.

$$j^{2}-5j-24-j^{2}=9j-10$$

Combine j^{2} and -j^{2} to get 0.

$$-5j-24=9j-10$$

Subtract 9j from both sides.

$$-5j-24-9j=-10$$

Combine -5j and -9j to get -14j.

$$-14j-24=-10$$

Add 24 to both sides.

$$-14j=-10+24$$

Add -10 and 24 to get 14.

$$-14j=14$$

Divide both sides by -14.

$$j=\frac{14}{-14}$$

Divide 14 by -14 to get -1.

$$j=-1$$