Solve j^-3k^-1*jk^-1/jk^0

$$\frac { j ^ { - 3 } k ^ { - 1 } \cdot j k ^ { - 1 } } { j k ^ { 0 } }$$

Evaluate

$$\frac{1}{k^{2}j^{3}}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -3 and 1 to get -2.

$$\frac{j^{-2}k^{-1}k^{-1}}{jk^{0}}$$

To multiply powers of the same base, add their exponents. Add -1 and -1 to get -2.

$$\frac{j^{-2}k^{-2}}{jk^{0}}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\frac{1}{k^{2}j^{3}}$$

Differentiate w.r.t. k

$$-\frac{2}{\left(jk\right)^{3}}$$