Solve for f
f=2x+h
h\neq 0
Solve for h
h=f-2x
f\neq 2x
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f\left(x+h\right)-fx=2xh+hh
Multiply both sides of the equation by h.
f\left(x+h\right)-fx=2xh+h^{2}
Multiply h and h to get h^{2}.
fx+fh-fx=2xh+h^{2}
Use the distributive property to multiply f by x+h.
fh=2xh+h^{2}
Combine fx and -fx to get 0.
hf=2hx+h^{2}
The equation is in standard form.
\frac{hf}{h}=\frac{h\left(2x+h\right)}{h}
Divide both sides by h.
f=\frac{h\left(2x+h\right)}{h}
Dividing by h undoes the multiplication by h.
f=2x+h
Divide h\left(2x+h\right) by h.
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