Solve for f
f=\frac{9}{x^{3}\left(\sin(x)-10\right)}
x\neq 0
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\frac{1}{9}f=\frac{1}{x^{3}\left(\sin(x)-10\right)}
The equation is in standard form.
\frac{\frac{1}{9}f}{\frac{1}{9}}=\frac{1}{\frac{1}{9}x^{3}\left(\sin(x)-10\right)}
Multiply both sides by 9.
f=\frac{1}{\frac{1}{9}x^{3}\left(\sin(x)-10\right)}
Dividing by \frac{1}{9} undoes the multiplication by \frac{1}{9}.
f=\frac{9}{x^{3}\left(\sin(x)-10\right)}
Divide \frac{1}{x^{3}\left(\sin(x)-10\right)} by \frac{1}{9} by multiplying \frac{1}{x^{3}\left(\sin(x)-10\right)} by the reciprocal of \frac{1}{9}.
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