Solve dy/d(x^2/1+x^3)=0

$$\frac { d y } { d } ( \frac { x ^ { 2 } } { 1 + x ^ { 3 } } ) = 0$$

Solve for d

$$d\neq 0$$

$$x=0\text{ or }\left(y=0\text{ and }x\neq -1\text{ and }d\neq 0\right)$$

Steps for Solving Linear Equation

Variable d cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by d\left(x+1\right)\left(x^{2}-x+1\right), the least common multiple of d,1+x^{3}.

$$\left(x^{3}+1\right)dy\times \frac{x^{2}}{1+x^{3}}=0$$

Express \left(x^{3}+1\right)\times \frac{x^{2}}{1+x^{3}} as a single fraction.

$$\frac{\left(x^{3}+1\right)x^{2}}{1+x^{3}}dy=0$$

Cancel out x^{3}+1 in both numerator and denominator.

$$x^{2}dy=0$$

The equation is in standard form.

$$yx^{2}d=0$$

Divide 0 by x^{2}y.

$$d=0$$

Variable d cannot be equal to 0.

$$d\in \emptyset$$

Solve for x

$$\left\{\begin{matrix}x=0\text{, }&d\neq 0\\x\neq -1\text{, }&y=0\text{ and }d\neq 0\end{matrix}\right.$$