\frac { d x } { x } = e ^ { 2 x } d x
Solve for d
\left\{\begin{matrix}d=0\text{, }&x\neq 0\\d\in \mathrm{R}\text{, }&1-xe^{2x}=0\text{ and }x\neq 0\end{matrix}\right.
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dx=e^{2x}dxx
Multiply both sides of the equation by x.
dx=e^{2x}dx^{2}
Multiply x and x to get x^{2}.
dx-e^{2x}dx^{2}=0
Subtract e^{2x}dx^{2} from both sides.
-dx^{2}e^{2x}+dx=0
Reorder the terms.
\left(-x^{2}e^{2x}+x\right)d=0
Combine all terms containing d.
\left(x-x^{2}e^{2x}\right)d=0
The equation is in standard form.
d=0
Divide 0 by -x^{2}e^{2x}+x.
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