Solve dV^2/dt=d(43+x)

$$\frac { d V ^ { 2 } } { d t } = d ( 43 + x )$$

Solve for d

$$\left\{\begin{matrix}\\d=0\text{, }&\text{unconditionally}\\d\in \mathrm{R}\text{, }&x=-43\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply d by 43+x.

$$\frac{\mathrm{d}}{\mathrm{d}t}(V^{2})=43d+dx$$

Swap sides so that all variable terms are on the left hand side.

$$43d+dx=\frac{\mathrm{d}}{\mathrm{d}t}(V^{2})$$

Combine all terms containing d.

$$\left(43+x\right)d=\frac{\mathrm{d}}{\mathrm{d}t}(V^{2})$$

The equation is in standard form.

$$\left(x+43\right)d=0$$

Divide 0 by 43+x.

$$d=0$$

Solve for V

$$V\in \mathrm{R}$$

$$x=-43\text{ or }d=0$$