Solve d/dx(2x^4+3x^2)=

$$\frac { d } { d x } ( 2 x ^ { 4 } + 3 x ^ { 2 } ) =$$

Evaluate

$$8x^{3}+6x$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$4\times 2x^{4-1}+2\times 3x^{2-1}$$

Multiply 4 times 2.

$$8x^{4-1}+2\times 3x^{2-1}$$

Subtract 1 from 4.

$$8x^{3}+2\times 3x^{2-1}$$

Multiply 2 times 3.

$$8x^{3}+6x^{2-1}$$

Subtract 1 from 2.

$$8x^{3}+6x^{1}$$

For any term t, t^{1}=t.

$$8x^{3}+6x$$

Differentiate w.r.t. x

$$24x^{2}+6$$