Solve d/8{4+5/2*frac{4/5-1}-1/5*3}-3

$$\frac { d } { \frac { 8 } { 4 + \frac { 5 } { 2 } \cdot \frac { 4 } { 5 } - 1 } - \frac { 1 } { 5 } \cdot 3 } - 3$$

Evaluate

$$d-3$$

Solution Steps

Multiply \frac{5}{2} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{d}{\frac{8}{4+\frac{5\times 4}{2\times 5}-1}-\frac{1}{5}\times 3}-3$$

Cancel out 5 in both numerator and denominator.

$$\frac{d}{\frac{8}{4+\frac{4}{2}-1}-\frac{1}{5}\times 3}-3$$

Divide 4 by 2 to get 2.

$$\frac{d}{\frac{8}{4+2-1}-\frac{1}{5}\times 3}-3$$

Add 4 and 2 to get 6.

$$\frac{d}{\frac{8}{6-1}-\frac{1}{5}\times 3}-3$$

Subtract 1 from 6 to get 5.

$$\frac{d}{\frac{8}{5}-\frac{1}{5}\times 3}-3$$

Multiply \frac{1}{5} and 3 to get \frac{3}{5}.

$$\frac{d}{\frac{8}{5}-\frac{3}{5}}-3$$

Since \frac{8}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{d}{\frac{8-3}{5}}-3$$

Subtract 3 from 8 to get 5.

$$\frac{d}{\frac{5}{5}}-3$$

Divide 5 by 5 to get 1.

$$\frac{d}{1}-3$$

Anything divided by one gives itself.

$$d-3$$

Factor

$$d-3$$