Evaluate
\frac{d-9}{d+4}
Expand
\frac{d-9}{d+4}
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\frac{d^{2}-12+3-8d}{\left(d+4\right)\left(d+1\right)}
Since \frac{d^{2}-12}{\left(d+4\right)\left(d+1\right)} and \frac{3-8d}{\left(d+4\right)\left(d+1\right)} have the same denominator, add them by adding their numerators.
\frac{d^{2}-9-8d}{\left(d+4\right)\left(d+1\right)}
Combine like terms in d^{2}-12+3-8d.
\frac{\left(d-9\right)\left(d+1\right)}{\left(d+1\right)\left(d+4\right)}
Factor the expressions that are not already factored in \frac{d^{2}-9-8d}{\left(d+4\right)\left(d+1\right)}.
\frac{d-9}{d+4}
Cancel out d+1 in both numerator and denominator.
\frac{d^{2}-12+3-8d}{\left(d+4\right)\left(d+1\right)}
Since \frac{d^{2}-12}{\left(d+4\right)\left(d+1\right)} and \frac{3-8d}{\left(d+4\right)\left(d+1\right)} have the same denominator, add them by adding their numerators.
\frac{d^{2}-9-8d}{\left(d+4\right)\left(d+1\right)}
Combine like terms in d^{2}-12+3-8d.
\frac{\left(d-9\right)\left(d+1\right)}{\left(d+1\right)\left(d+4\right)}
Factor the expressions that are not already factored in \frac{d^{2}-9-8d}{\left(d+4\right)\left(d+1\right)}.
\frac{d-9}{d+4}
Cancel out d+1 in both numerator and denominator.
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Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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