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3cc=2\left(9+c^{2}-4\right)
Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 12c, the least common multiple of 4,6c.
3c^{2}=2\left(9+c^{2}-4\right)
Multiply c and c to get c^{2}.
3c^{2}=2\left(5+c^{2}\right)
Subtract 4 from 9 to get 5.
3c^{2}=10+2c^{2}
Use the distributive property to multiply 2 by 5+c^{2}.
3c^{2}-2c^{2}=10
Subtract 2c^{2} from both sides.
c^{2}=10
Combine 3c^{2} and -2c^{2} to get c^{2}.
c=\sqrt{10} c=-\sqrt{10}
Take the square root of both sides of the equation.
3cc=2\left(9+c^{2}-4\right)
Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 12c, the least common multiple of 4,6c.
3c^{2}=2\left(9+c^{2}-4\right)
Multiply c and c to get c^{2}.
3c^{2}=2\left(5+c^{2}\right)
Subtract 4 from 9 to get 5.
3c^{2}=10+2c^{2}
Use the distributive property to multiply 2 by 5+c^{2}.
3c^{2}-10=2c^{2}
Subtract 10 from both sides.
3c^{2}-10-2c^{2}=0
Subtract 2c^{2} from both sides.
c^{2}-10=0
Combine 3c^{2} and -2c^{2} to get c^{2}.
c=\frac{0±\sqrt{0^{2}-4\left(-10\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
c=\frac{0±\sqrt{-4\left(-10\right)}}{2}
Square 0.
c=\frac{0±\sqrt{40}}{2}
Multiply -4 times -10.
c=\frac{0±2\sqrt{10}}{2}
Take the square root of 40.
c=\sqrt{10}
Now solve the equation c=\frac{0±2\sqrt{10}}{2} when ± is plus.
c=-\sqrt{10}
Now solve the equation c=\frac{0±2\sqrt{10}}{2} when ± is minus.
c=\sqrt{10} c=-\sqrt{10}
The equation is now solved.