Solve c/1=2/a+b/5

$$\frac { c } { 1 } = \frac { 2 } { a } + \frac { b } { 5 }$$

Solve for a

$$a=-\frac{10}{b-5c}$$

$$c\neq \frac{b}{5}$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5a, the least common multiple of a,5.

$$5ac=5\times 2+ab$$

Multiply 5 and 2 to get 10.

$$5ac=10+ab$$

Subtract ab from both sides.

$$5ac-ab=10$$

Combine all terms containing a.

$$\left(5c-b\right)a=10$$

Divide both sides by 5c-b.

$$\frac{\left(5c-b\right)a}{5c-b}=\frac{10}{5c-b}$$

Dividing by 5c-b undoes the multiplication by 5c-b.

$$a=\frac{10}{5c-b}$$

Variable a cannot be equal to 0.

$$a=\frac{10}{5c-b}\text{, }a\neq 0$$

Solve for b

$$b=5c-\frac{10}{a}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5a, the least common multiple of a,5.

$$5ac=5\times 2+ab$$

Multiply 5 and 2 to get 10.

$$5ac=10+ab$$

Swap sides so that all variable terms are on the left hand side.

$$10+ab=5ac$$

Subtract 10 from both sides.

$$ab=5ac-10$$

Divide both sides by a.

$$\frac{ab}{a}=\frac{5ac-10}{a}$$

Dividing by a undoes the multiplication by a.

$$b=\frac{5ac-10}{a}$$

Divide 5ac-10 by a.

$$b=5c-\frac{10}{a}$$