Solve b/c-2+c/b

$$\frac { b } { c } - 2 + \frac { c } { b }$$

Evaluate

$$\frac{\left(c-b\right)^{2}}{bc}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{c}{c}.

$$\frac{b}{c}-\frac{2c}{c}+\frac{c}{b}$$

Since \frac{b}{c} and \frac{2c}{c} have the same denominator, subtract them by subtracting their numerators.

$$\frac{b-2c}{c}+\frac{c}{b}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of c and b is bc. Multiply \frac{b-2c}{c} times \frac{b}{b}. Multiply \frac{c}{b} times \frac{c}{c}.

$$\frac{\left(b-2c\right)b}{bc}+\frac{cc}{bc}$$

Since \frac{\left(b-2c\right)b}{bc} and \frac{cc}{bc} have the same denominator, add them by adding their numerators.

$$\frac{\left(b-2c\right)b+cc}{bc}$$

Do the multiplications in \left(b-2c\right)b+cc.

$$\frac{b^{2}-2cb+c^{2}}{bc}$$

Factor

$$\frac{\left(c-b\right)^{2}}{bc}$$