Solve b/b+2+8b

$$\frac { b } { b + 2 } + 8 b$$

Evaluate

$$\frac{b\left(8b+17\right)}{b+2}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 8b times \frac{b+2}{b+2}.

$$\frac{b}{b+2}+\frac{8b\left(b+2\right)}{b+2}$$

Since \frac{b}{b+2} and \frac{8b\left(b+2\right)}{b+2} have the same denominator, add them by adding their numerators.

$$\frac{b+8b\left(b+2\right)}{b+2}$$

Do the multiplications in b+8b\left(b+2\right).

$$\frac{b+8b^{2}+16b}{b+2}$$

Combine like terms in b+8b^{2}+16b.

$$\frac{17b+8b^{2}}{b+2}$$

Factor

$$\frac{b\left(8b+17\right)}{b+2}$$