Solve for b
b=4-c
Solve for c
c=4-b
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b+c+2b+2c=12
Multiply both sides of the equation by 2.
3b+c+2c=12
Combine b and 2b to get 3b.
3b+3c=12
Combine c and 2c to get 3c.
3b=12-3c
Subtract 3c from both sides.
\frac{3b}{3}=\frac{12-3c}{3}
Divide both sides by 3.
b=\frac{12-3c}{3}
Dividing by 3 undoes the multiplication by 3.
b=4-c
Divide 12-3c by 3.
b+c+2b+2c=12
Multiply both sides of the equation by 2.
3b+c+2c=12
Combine b and 2b to get 3b.
3b+3c=12
Combine c and 2c to get 3c.
3c=12-3b
Subtract 3b from both sides.
\frac{3c}{3}=\frac{12-3b}{3}
Divide both sides by 3.
c=\frac{12-3b}{3}
Dividing by 3 undoes the multiplication by 3.
c=4-b
Divide 12-3b by 3.
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