Solve b^2-b/a^2-9*a+3/b

$$\frac { b ^ { 2 } - b } { a ^ { 2 } - 9 } \cdot \frac { a + 3 } { b }$$

Evaluate

$$\frac{b-1}{a-3}$$

Short Solution Steps

Multiply \frac{b^{2}-b}{a^{2}-9} times \frac{a+3}{b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(b^{2}-b\right)\left(a+3\right)}{\left(a^{2}-9\right)b}$$

Factor the expressions that are not already factored.

$$\frac{b\left(b-1\right)\left(a+3\right)}{b\left(a-3\right)\left(a+3\right)}$$

Cancel out b\left(a+3\right) in both numerator and denominator.

$$\frac{b-1}{a-3}$$

Expand

$$\frac{b-1}{a-3}$$

Short Solution Steps

Multiply \frac{b^{2}-b}{a^{2}-9} times \frac{a+3}{b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(b^{2}-b\right)\left(a+3\right)}{\left(a^{2}-9\right)b}$$

Factor the expressions that are not already factored.

$$\frac{b\left(b-1\right)\left(a+3\right)}{b\left(a-3\right)\left(a+3\right)}$$

Cancel out b\left(a+3\right) in both numerator and denominator.

$$\frac{b-1}{a-3}$$