Solve b^2-a^2/a^2-ab*2ab/ab+b^2

$$\frac { b ^ { 2 } - a ^ { 2 } } { a ^ { 2 } - a b } \cdot \frac { 2 a b } { a b + b ^ { 2 } }$$

Evaluate

$$-2$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{b^{2}-a^{2}}{a^{2}-ab}.

$$\frac{\left(a+b\right)\left(-a+b\right)}{a\left(a-b\right)}\times \frac{2ab}{ab+b^{2}}$$

Extract the negative sign in b-a.

$$\frac{-\left(a+b\right)\left(a-b\right)}{a\left(a-b\right)}\times \frac{2ab}{ab+b^{2}}$$

Cancel out a-b in both numerator and denominator.

$$\frac{-\left(a+b\right)}{a}\times \frac{2ab}{ab+b^{2}}$$

Factor the expressions that are not already factored in \frac{2ab}{ab+b^{2}}.

$$\frac{-\left(a+b\right)}{a}\times \frac{2ab}{b\left(a+b\right)}$$

Cancel out b in both numerator and denominator.

$$\frac{-\left(a+b\right)}{a}\times \frac{2a}{a+b}$$

Multiply \frac{-\left(a+b\right)}{a} times \frac{2a}{a+b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(a+b\right)\times 2a}{a\left(a+b\right)}$$

Cancel out a\left(a+b\right) in both numerator and denominator.

$$-2$$

Factor

$$-2$$