Solve b+b^8/b^2+b^4

$$\frac { b + b ^ { 8 } } { b ^ { 2 } + b ^ { 4 } }$$

Evaluate

$$\frac{b^{7}+1}{b\left(b^{2}+1\right)}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{b\left(b+1\right)\left(b^{6}-b^{5}+b^{4}-b^{3}+b^{2}-b+1\right)}{b^{2}\left(b^{2}+1\right)}$$

Cancel out b in both numerator and denominator.

$$\frac{\left(b+1\right)\left(b^{6}-b^{5}+b^{4}-b^{3}+b^{2}-b+1\right)}{b\left(b^{2}+1\right)}$$

Expand the expression.

$$\frac{b^{7}+1}{b^{3}+b}$$

Expand

$$\frac{b^{7}+1}{b\left(b^{2}+1\right)}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{b\left(b+1\right)\left(b^{6}-b^{5}+b^{4}-b^{3}+b^{2}-b+1\right)}{b^{2}\left(b^{2}+1\right)}$$

Cancel out b in both numerator and denominator.

$$\frac{\left(b+1\right)\left(b^{6}-b^{5}+b^{4}-b^{3}+b^{2}-b+1\right)}{b\left(b^{2}+1\right)}$$

Expand the expression.

$$\frac{b^{7}+1}{b^{3}+b}$$