Solve b+2/4+2b-5/3

$$\frac { b + 2 } { 4 } + \frac { 2 b - 5 } { 3 }$$

Evaluate

$$\frac{11b}{12}-\frac{7}{6}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4 and 3 is 12. Multiply \frac{b+2}{4} times \frac{3}{3}. Multiply \frac{2b-5}{3} times \frac{4}{4}.

$$\frac{3\left(b+2\right)}{12}+\frac{4\left(2b-5\right)}{12}$$

Since \frac{3\left(b+2\right)}{12} and \frac{4\left(2b-5\right)}{12} have the same denominator, add them by adding their numerators.

$$\frac{3\left(b+2\right)+4\left(2b-5\right)}{12}$$

Do the multiplications in 3\left(b+2\right)+4\left(2b-5\right).

$$\frac{3b+6+8b-20}{12}$$

Combine like terms in 3b+6+8b-20.

$$\frac{11b-14}{12}$$

Expand

$$\frac{11b}{12}-\frac{7}{6}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4 and 3 is 12. Multiply \frac{b+2}{4} times \frac{3}{3}. Multiply \frac{2b-5}{3} times \frac{4}{4}.

$$\frac{3\left(b+2\right)}{12}+\frac{4\left(2b-5\right)}{12}$$

Since \frac{3\left(b+2\right)}{12} and \frac{4\left(2b-5\right)}{12} have the same denominator, add them by adding their numerators.

$$\frac{3\left(b+2\right)+4\left(2b-5\right)}{12}$$

Do the multiplications in 3\left(b+2\right)+4\left(2b-5\right).

$$\frac{3b+6+8b-20}{12}$$

Combine like terms in 3b+6+8b-20.

$$\frac{11b-14}{12}$$