Solve for a
a=4+\frac{7}{x}
x\neq 0
Solve for x
x=\frac{7}{a-4}
a\neq 4
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ax-1-4x=6
Multiply both sides of the equation by 2.
ax-4x=6+1
Add 1 to both sides.
ax-4x=7
Add 6 and 1 to get 7.
ax=7+4x
Add 4x to both sides.
xa=4x+7
The equation is in standard form.
\frac{xa}{x}=\frac{4x+7}{x}
Divide both sides by x.
a=\frac{4x+7}{x}
Dividing by x undoes the multiplication by x.
a=4+\frac{7}{x}
Divide 7+4x by x.
ax-1-4x=6
Multiply both sides of the equation by 2.
ax-4x=6+1
Add 1 to both sides.
ax-4x=7
Add 6 and 1 to get 7.
\left(a-4\right)x=7
Combine all terms containing x.
\frac{\left(a-4\right)x}{a-4}=\frac{7}{a-4}
Divide both sides by a-4.
x=\frac{7}{a-4}
Dividing by a-4 undoes the multiplication by a-4.
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