Solve for a
a=\frac{c\left(c-bx\right)}{b}
b\neq 0\text{ and }c\neq bx
Solve for b
\left\{\begin{matrix}b=\frac{c^{2}}{cx+a}\text{, }&a\neq 0\text{ and }c\neq 0\text{ and }a\neq -cx\\b\neq 0\text{, }&c=0\text{ and }a=0\text{ and }x\neq 0\end{matrix}\right.
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ab=c\left(-bx+c\right)
Multiply both sides of the equation by -bx+c.
ab=-cbx+c^{2}
Use the distributive property to multiply c by -bx+c.
ba=c^{2}-bcx
The equation is in standard form.
\frac{ba}{b}=\frac{c\left(c-bx\right)}{b}
Divide both sides by b.
a=\frac{c\left(c-bx\right)}{b}
Dividing by b undoes the multiplication by b.
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