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Solve for L
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Solve for a
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\frac{1}{3}a-\frac{1}{3}b=L
Divide each term of a-b by 3 to get \frac{1}{3}a-\frac{1}{3}b.
L=\frac{1}{3}a-\frac{1}{3}b
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}a-\frac{1}{3}b=L
Divide each term of a-b by 3 to get \frac{1}{3}a-\frac{1}{3}b.
\frac{1}{3}a=L+\frac{1}{3}b
Add \frac{1}{3}b to both sides.
\frac{1}{3}a=\frac{b}{3}+L
The equation is in standard form.
\frac{\frac{1}{3}a}{\frac{1}{3}}=\frac{\frac{b}{3}+L}{\frac{1}{3}}
Multiply both sides by 3.
a=\frac{\frac{b}{3}+L}{\frac{1}{3}}
Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.
a=3L+b
Divide L+\frac{b}{3} by \frac{1}{3} by multiplying L+\frac{b}{3} by the reciprocal of \frac{1}{3}.