Solve a(b+2)^2-4(b-a)-b^2-8/b^4+64

$$\frac { a ( b + 2 ) ^ { 2 } - 4 ( b - a ) - b ^ { 2 } - 8 } { b ^ { 4 } + 64 }$$

Evaluate

$$\frac{a-1}{b^{2}-4b+8}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(a-1\right)\left(b^{2}+4b+8\right)}{\left(b^{2}-4b+8\right)\left(b^{2}+4b+8\right)}$$

Cancel out b^{2}+4b+8 in both numerator and denominator.

$$\frac{a-1}{b^{2}-4b+8}$$

Expand

$$\frac{a-1}{b^{2}-4b+8}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(a-1\right)\left(b^{2}+4b+8\right)}{\left(b^{2}-4b+8\right)\left(b^{2}+4b+8\right)}$$

Cancel out b^{2}+4b+8 in both numerator and denominator.

$$\frac{a-1}{b^{2}-4b+8}$$