Solve a/b+4b/2=4

$$\frac { a } { b } + \frac { 4 b } { 2 } = 4$$

Solve for a

$$a=-2b\left(b-2\right)$$

$$b\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2b, the least common multiple of b,2.

$$2a+b\times 4b=8b$$

Multiply b and b to get b^{2}.

$$2a+b^{2}\times 4=8b$$

Subtract b^{2}\times 4 from both sides.

$$2a=8b-b^{2}\times 4$$

Multiply -1 and 4 to get -4.

$$2a=8b-4b^{2}$$

Divide both sides by 2.

$$\frac{2a}{2}=\frac{4b\left(2-b\right)}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$a=\frac{4b\left(2-b\right)}{2}$$

Divide 4b\left(2-b\right) by 2.

$$a=2b\left(2-b\right)$$

Solve for b

$$\left\{\begin{matrix}b=-\frac{\sqrt{4-2a}}{2}+1\text{, }&a\neq 0\text{ and }a\leq 2\\b=\frac{\sqrt{4-2a}}{2}+1\text{, }&a\leq 2\end{matrix}\right.$$