Solve a/a^2-64+3/a-8=2/a+8

$$\frac { a } { a ^ { 2 } - 64 } + \frac { 3 } { a - 8 } = \frac { 2 } { a + 8 }$$

Solve for a

$$a=-20$$

Steps for Solving Linear Equation

Variable a cannot be equal to any of the values -8,8 since division by zero is not defined. Multiply both sides of the equation by \left(a-8\right)\left(a+8\right), the least common multiple of a^{2}-64,a-8,a+8.

$$a+\left(a+8\right)\times 3=\left(a-8\right)\times 2$$

Use the distributive property to multiply a+8 by 3.

$$a+3a+24=\left(a-8\right)\times 2$$

Combine a and 3a to get 4a.

$$4a+24=\left(a-8\right)\times 2$$

Use the distributive property to multiply a-8 by 2.

$$4a+24=2a-16$$

Subtract 2a from both sides.

$$4a+24-2a=-16$$

Combine 4a and -2a to get 2a.

$$2a+24=-16$$

Subtract 24 from both sides.

$$2a=-16-24$$

Subtract 24 from -16 to get -40.

$$2a=-40$$

Divide both sides by 2.

$$a=\frac{-40}{2}$$

Divide -40 by 2 to get -20.

$$a=-20$$