Solve for a
a=5-\frac{160}{c}
c\neq 0
Solve for c
c=-\frac{160}{a-5}
a\neq 5
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ac+160-5c=0
Multiply both sides of the equation by 5.
ac-5c=-160
Subtract 160 from both sides. Anything subtracted from zero gives its negation.
ac=-160+5c
Add 5c to both sides.
ca=5c-160
The equation is in standard form.
\frac{ca}{c}=\frac{5c-160}{c}
Divide both sides by c.
a=\frac{5c-160}{c}
Dividing by c undoes the multiplication by c.
a=5-\frac{160}{c}
Divide -160+5c by c.
ac+160-5c=0
Multiply both sides of the equation by 5.
ac-5c=-160
Subtract 160 from both sides. Anything subtracted from zero gives its negation.
\left(a-5\right)c=-160
Combine all terms containing c.
\frac{\left(a-5\right)c}{a-5}=-\frac{160}{a-5}
Divide both sides by a-5.
c=-\frac{160}{a-5}
Dividing by a-5 undoes the multiplication by a-5.
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