Solve a/4+2b/6=1

$$\frac { a } { 4 } + \frac { 2 b } { 6 } = 1$$

Solve for a

$$a=-\frac{4b}{3}+4$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 4,6.

$$3a+2\times 2b=12$$

Multiply 2 and 2 to get 4.

$$3a+4b=12$$

Subtract 4b from both sides.

$$3a=12-4b$$

Divide both sides by 3.

$$\frac{3a}{3}=\frac{12-4b}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$a=\frac{12-4b}{3}$$

Divide 12-4b by 3.

$$a=-\frac{4b}{3}+4$$

Solve for b

$$b=-\frac{3a}{4}+3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 4,6.

$$3a+2\times 2b=12$$

Multiply 2 and 2 to get 4.

$$3a+4b=12$$

Subtract 3a from both sides.

$$4b=12-3a$$

Divide both sides by 4.

$$\frac{4b}{4}=\frac{12-3a}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$b=\frac{12-3a}{4}$$

Divide 12-3a by 4.

$$b=-\frac{3a}{4}+3$$