Solve a/3+b/6=1

$$\frac { a } { 3 } + \frac { b } { 6 } = 1$$

Solve for a

$$a=-\frac{b}{2}+3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,6.

$$2a+b=6$$

Subtract b from both sides.

$$2a=6-b$$

Divide both sides by 2.

$$\frac{2a}{2}=\frac{6-b}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$a=\frac{6-b}{2}$$

Divide 6-b by 2.

$$a=-\frac{b}{2}+3$$

Solve for b

$$b=6-2a$$

Solution Steps

Multiply both sides of the equation by 6, the least common multiple of 3,6.

$$2a+b=6$$

Subtract 2a from both sides.

$$b=6-2a$$