Solve for a
a=-\frac{2b}{3}+4
Solve for b
b=-\frac{3a}{2}+6
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3a+2b=12
Multiply both sides of the equation by 6, the least common multiple of 2,3.
3a=12-2b
Subtract 2b from both sides.
\frac{3a}{3}=\frac{12-2b}{3}
Divide both sides by 3.
a=\frac{12-2b}{3}
Dividing by 3 undoes the multiplication by 3.
a=-\frac{2b}{3}+4
Divide 12-2b by 3.
3a+2b=12
Multiply both sides of the equation by 6, the least common multiple of 2,3.
2b=12-3a
Subtract 3a from both sides.
\frac{2b}{2}=\frac{12-3a}{2}
Divide both sides by 2.
b=\frac{12-3a}{2}
Dividing by 2 undoes the multiplication by 2.
b=-\frac{3a}{2}+6
Divide 12-3a by 2.
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