Solve a/1+b/16=d/e

$$\frac { a } { 1 } + \frac { b } { 16 } = \frac { d } { e }$$

Solve for a

$$a=\frac{d}{e}-\frac{b}{16}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 16.

$$16a+b=16e^{-1}d$$

Subtract b from both sides.

$$16a=16e^{-1}d-b$$

Reorder the terms.

$$16a=16\times \frac{1}{e}d-b$$

Express 16\times \frac{1}{e} as a single fraction.

$$16a=\frac{16}{e}d-b$$

Express \frac{16}{e}d as a single fraction.

$$16a=\frac{16d}{e}-b$$

To add or subtract expressions, expand them to make their denominators the same. Multiply b times \frac{e}{e}.

$$16a=\frac{16d}{e}-\frac{be}{e}$$

Since \frac{16d}{e} and \frac{be}{e} have the same denominator, subtract them by subtracting their numerators.

$$16a=\frac{16d-be}{e}$$

The equation is in standard form.

$$16a=\frac{16d-eb}{e}$$

Divide both sides by 16.

$$\frac{16a}{16}=\frac{\frac{16d}{e}-b}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$a=\frac{\frac{16d}{e}-b}{16}$$

Divide \frac{16d}{e}-b by 16.

$$a=\frac{d}{e}-\frac{b}{16}$$

Solve for b

$$b=\frac{16d}{e}-16a$$