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Differentiate w.r.t. x
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\frac{a^{3}b\times 6cd}{3cd\left(-2\right)ax}
Divide \frac{a^{3}b}{3cd} by \frac{-2ax}{6cd} by multiplying \frac{a^{3}b}{3cd} by the reciprocal of \frac{-2ax}{6cd}.
\frac{ba^{2}}{-x}
Cancel out 2\times 3acd in both numerator and denominator.