Solve frac{a^{2}b^2+6ab^3+9b^4}{(a+3b)^3}=

$$\frac { a ^ { 2 } b ^ { 2 } + 6 a b ^ { 3 } + 9 b ^ { 4 } } { ( a + 3 b ) ^ { 3 } } =$$

Evaluate

$$\frac{b^{2}}{a+3b}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{b^{2}\left(a+3b\right)^{2}}{\left(a+3b\right)^{3}}$$

Cancel out \left(a+3b\right)^{2} in both numerator and denominator.

$$\frac{b^{2}}{a+3b}$$

Expand

$$\frac{b^{2}}{a+3b}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{b^{2}\left(a+3b\right)^{2}}{\left(a+3b\right)^{3}}$$

Cancel out \left(a+3b\right)^{2} in both numerator and denominator.

$$\frac{b^{2}}{a+3b}$$