Solve a^2-2a-3/a^2-9*9-3a/a^2-5a-6

$$\frac { a ^ { 2 } - 2 a - 3 } { a ^ { 2 } - 9 } \cdot \frac { 9 - 3 a } { a ^ { 2 } - 5 a - 6 }$$

Evaluate

$$\frac{3\left(3-a\right)}{\left(a-6\right)\left(a+3\right)}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}-2a-3}{a^{2}-9}.

$$\frac{\left(a-3\right)\left(a+1\right)}{\left(a-3\right)\left(a+3\right)}\times \frac{9-3a}{a^{2}-5a-6}$$

Cancel out a-3 in both numerator and denominator.

$$\frac{a+1}{a+3}\times \frac{9-3a}{a^{2}-5a-6}$$

Multiply \frac{a+1}{a+3} times \frac{9-3a}{a^{2}-5a-6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(a+1\right)\left(9-3a\right)}{\left(a+3\right)\left(a^{2}-5a-6\right)}$$

Factor the expressions that are not already factored.

$$\frac{3\left(a+1\right)\left(-a+3\right)}{\left(a-6\right)\left(a+1\right)\left(a+3\right)}$$

Cancel out a+1 in both numerator and denominator.

$$\frac{3\left(-a+3\right)}{\left(a-6\right)\left(a+3\right)}$$

Expand the expression.

$$\frac{-3a+9}{a^{2}-3a-18}$$

Expand

$$-\frac{3\left(a-3\right)}{\left(a-6\right)\left(a+3\right)}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}-2a-3}{a^{2}-9}.

$$\frac{\left(a-3\right)\left(a+1\right)}{\left(a-3\right)\left(a+3\right)}\times \frac{9-3a}{a^{2}-5a-6}$$

Cancel out a-3 in both numerator and denominator.

$$\frac{a+1}{a+3}\times \frac{9-3a}{a^{2}-5a-6}$$

Multiply \frac{a+1}{a+3} times \frac{9-3a}{a^{2}-5a-6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(a+1\right)\left(9-3a\right)}{\left(a+3\right)\left(a^{2}-5a-6\right)}$$

Factor the expressions that are not already factored.

$$\frac{3\left(a+1\right)\left(-a+3\right)}{\left(a-6\right)\left(a+1\right)\left(a+3\right)}$$

Cancel out a+1 in both numerator and denominator.

$$\frac{3\left(-a+3\right)}{\left(a-6\right)\left(a+3\right)}$$

Expand the expression.

$$\frac{-3a+9}{a^{2}-3a-18}$$